Answers for "jquery post form data ajax"

1

ajax submit form data

$(function() {
  $('form.my_form').submit(function(event) {
    event.preventDefault(); // Prevent the form from submitting via the browser
    var form = $(this);
    $.ajax({
      type: form.attr('method'),
      url: form.attr('action'),
      data: form.serialize()
    }).done(function(data) {
      // Optionally alert the user of success here...
    }).fail(function(data) {
      // Optionally alert the user of an error here...
    });
  });
});
Posted by: Guest on December-22-2020
0

make ajax request post jquery

$.ajax({
  method: "POST",
  url: "some.php",
  data: { name: "John", location: "Boston" }
})
Posted by: Guest on July-21-2020
1

jquery $.post

// Assign handlers immediately after making the request,
// and remember the jqxhr object for this request
var jqxhr = $.post( "example.php", function() {
  alert( "success" );
})
  .done(function() {
    alert( "second success" );
  })
  .fail(function() {
    alert( "error" );
  })
  .always(function() {
    alert( "finished" );
  });
 
// Perform other work here ...
 
// Set another completion function for the request above
jqxhr.always(function() {
  alert( "second finished" );
});
Posted by: Guest on May-21-2020
0

ajax submit form data

<form id="contactForm1" action="/your_url" method="post">
    <!-- Form input fields here (do not forget your name attributes). -->
</form>

<script type="text/javascript">
    var frm = $('#contactForm1');

    frm.submit(function (e) {

        e.preventDefault();

        $.ajax({
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: frm.serialize(),
            success: function (data) {
                console.log('Submission was successful.');
                console.log(data);
            },
            error: function (data) {
                console.log('An error occurred.');
                console.log(data);
            },
        });
    });
</script>
Posted by: Guest on January-09-2021

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