Answers for "on form submit send ajax call"

15

jQuery AJAX form submit

// jQuery ajax form submit example, runs when form is submitted
$("#myFormID").submit(function(e) {
    e.preventDefault(); // prevent actual form submit
    var form = $(this);
    var url = form.attr('action'); //get submit url [replace url here if desired]
    $.ajax({
         type: "POST",
         url: url,
         data: form.serialize(), // serializes form input
         success: function(data){
             console.log(data);
         }
    });
});
Posted by: Guest on July-25-2019
0

Sending an Ajax request before form submit

$('form').submit(function(e) { 

     // this code prevents form from actually being submitted
     e.preventDefault();
     e.returnValue = false;

     // some validation code here: if valid, add podkres1 class

     if ($('input.podkres1').length > 0) { 
        // do nothing
     } else {

        var $form = $(this);

        // this is the important part. you want to submit
        // the form but only after the ajax call is completed
         $.ajax({ 
             type: 'post',
             url: someUrl, 
             context: $form, // context will be "this" in your handlers
             success: function() { // your success handler
             },
             error: function() { // your error handler
             },
             complete: function() { 
                // make sure that you are no longer handling the submit event; clear handler
                this.off('submit');
                // actually submit the form
                this.submit();
             }
         });
     }
});
Posted by: Guest on July-19-2020
0

ajax submit form data

<form id="contactForm1" action="/your_url" method="post">
    <!-- Form input fields here (do not forget your name attributes). -->
</form>

<script type="text/javascript">
    var frm = $('#contactForm1');

    frm.submit(function (e) {

        e.preventDefault();

        $.ajax({
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: frm.serialize(),
            success: function (data) {
                console.log('Submission was successful.');
                console.log(data);
            },
            error: function (data) {
                console.log('An error occurred.');
                console.log(data);
            },
        });
    });
</script>
Posted by: Guest on January-09-2021

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