Answers for "jquery ajax form submit example php"

15

jQuery AJAX form submit

// jQuery ajax form submit example, runs when form is submitted
$("#myFormID").submit(function(e) {
    e.preventDefault(); // prevent actual form submit
    var form = $(this);
    var url = form.attr('action'); //get submit url [replace url here if desired]
    $.ajax({
         type: "POST",
         url: url,
         data: form.serialize(), // serializes form input
         success: function(data){
             console.log(data);
         }
    });
});
Posted by: Guest on July-25-2019
1

ajax php form submit

The form is submitting after the ajax request.

<html>
  <head>
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <script>
      $(function () {

        $('form').on('submit', function (e) {

          e.preventDefault();

          $.ajax({
            type: 'post',
            url: 'post.php',
            data: $('form').serialize(),
            success: function () {
              alert('form was submitted');
            }
          });

        });

      });
    </script>
  </head>
  <body>
    <form>
      <input name="time" value="00:00:00.00"><br>
      <input name="date" value="0000-00-00"><br>
      <input name="submit" type="submit" value="Submit">
    </form>
  </body>
</html>
Posted by: Guest on March-21-2021
0

jquery ajax form submit example

$.ajax({
			    type: "POST",
			    url: "upload.php",
			    data: { name:name, mobile:mobile, address:address, city:city },		    
			    dataType: "json",
			    success: function(result){
			        			    }
			});
Posted by: Guest on November-23-2020
0

ajax submit form data

<form id="contactForm1" action="/your_url" method="post">
    <!-- Form input fields here (do not forget your name attributes). -->
</form>

<script type="text/javascript">
    var frm = $('#contactForm1');

    frm.submit(function (e) {

        e.preventDefault();

        $.ajax({
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: frm.serialize(),
            success: function (data) {
                console.log('Submission was successful.');
                console.log(data);
            },
            error: function (data) {
                console.log('An error occurred.');
                console.log(data);
            },
        });
    });
</script>
Posted by: Guest on January-09-2021

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