how to check if item is in list js
var myList=["a", "b", "c"];
mylist.includes("d")//returns true or falsehow to check if item is in list js
var myList=["a", "b", "c"];
mylist.includes("d")//returns true or falsecheck if array contain the all element javascript
const myArray: number[] = [2, 4, 6, 8, 10, 12, 14, 16];
const elements: number[] = [4, 8, 12, 16];
function containsAll(arr: number[]) {
return (
arr.includes(elements[0]) &&
arr.includes(elements[1]) &&
arr.includes(elements[2]) &&
arr.includes(elements[3])
);
}
console.log(containsAll(myArray));
or you could use the following line:
function c2(arr: number[]) {
return elements.every((val: number) => arr.includes(val));
}check if string contains a value in array
$count = 0;
str_replace($owned_urls, '', $string, $count);
// if replace is successful means the array value is present(Match Found).
if ($count > 0) {
echo "One of Array value is present in the string.";
}if array includes string
function droids(arr) {
let result = 'These are not the droids you\'re looking for';
for(let i=0; i<arr.length;i++) {
if (arr[i] === 'Droids') {
result = 'Found Droid';
}
}
return result;
}
// Uncomment these to check your work!
const starWars = ["Luke", "Finn", "Rey", "Kylo", "Droids"]
const thrones = ["Jon", "Danny", "Tyrion", "The Mountain", "Cersei"]
console.log(droids(starWars)) // should log: "Found Droids!"
console.log(droids(thrones)) // should log: "These are not the droi
//A simpler approach
console.log(starWars.includes('Droids') ? 'Droid Found' : 'These are not the droids you\'re looking for');
console.log(thrones.includes('Droids') ? 'Droid Found' : 'These are not the droids you\'re looking for');how to Check if an array contains a string
// To check if an array contains a string
const colors = ['red', 'green', 'blue'];
const result = colors.includes('red');
console.log(result); // true
// Or
const colors = ['Red', 'GREEN', 'Blue'];
const result = colors.map(e => e.toLocaleLowerCase())
.includes('green');
console.log(result); // trueCopyright © 2021 Codeinu
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