Answers for "js arrotondare superiore numero"

1

js arrotondare superiore numero

// value is the value to round
 // places if positive the number of decimal places to round to
 // places if negative the number of digits to round to
 function roundTo(value, places){
     var power = Math.pow(10, places);
     return Math.round(value * power) / power;
 }
 var myNum = 10000/3;    // 3333.3333333333335
 roundTo(myNum, 2);  // 3333.33
 roundTo(myNum, 0);  // 3333
 roundTo(myNum, -2); // 3300
Posted by: Guest on January-04-2021
1

js arrotondare superiore numero

function ceilTo(value, places){
     var power = Math.pow(10, places);
     return Math.ceil(value * power) / power;
 }
 function floorTo(value, places){
     var power = Math.pow(10, places);
     return Math.floor(value * power) / power;
 }
Posted by: Guest on January-04-2021
0

js arrotondare superiore numero

var myNum = 2/3;               // 0.6666666666666666
 var multiplier = 100;
 var a = Math.round(myNum * multiplier) / multiplier;  // 0.67
 var b = Math.ceil (myNum * multiplier) / multiplier;  // 0.67
 var c = Math.floor(myNum * multiplier) / multiplier;  // 0.66
Posted by: Guest on January-04-2021
0

js arrotondare superiore numero

Math.trunc(2.3);                // 2 (floor)
Math.trunc(-2.3);               // -2 (ceil)
Math.trunc(2147483648.1);       // 2147483648 (floor)
Math.trunc(-2147483649.1);      // -2147483649 (ceil)
Math.trunc(NaN);                // NaN
Posted by: Guest on January-04-2021
0

js arrotondare superiore numero

var c = Math.round(-2.7);       // c is now -3
var c = Math.round(-2.5);       // c is now -2
Posted by: Guest on January-04-2021
0

js arrotondare superiore numero

var a = Math.ceil(2.3);        // a is now 3
var b = Math.ceil(2.7);        // b is now 3
Posted by: Guest on January-04-2021
0

js arrotondare superiore numero

var myNum = 10000/3;           // 3333.3333333333335
 var multiplier = 1/100;
 var a = Math.round(myNum * multiplier) / multiplier;  // 3300
 var b = Math.ceil (myNum * multiplier) / multiplier;  // 3400
 var c = Math.floor(myNum * multiplier) / multiplier;  // 3300
Posted by: Guest on January-04-2021

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