url validator javascript
function validURL(str) {
var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol
'((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name
'((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address
'(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path
'(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string
'(\\#[-a-z\\d_]*)?$','i'); // fragment locator
return !!pattern.test(str);
}to ensure user input is a link in html
<form action="../../form-result.php" method="post" target="_blank">
<p>
Website: <input type="url" name="website" placeholder="Do you have a website?">
<input type="submit" value="Send data">
</p>
</form>Copyright © 2021 Codeinu
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