Answers for "how to send ajax request in javascript"

4

how to send data using ajax

$.ajax({
	url: "/something", // the url we want to send and get data from
    type: "GET", // type of the data we send (POST/GET)
    data: {p1: "This is our data"}, // the data we want to send
    success: function(data){ // when successfully sent data and returned
    	// do something with the returned data
   		console.log(data);
    }
}).done(function(){
	// this part will run when we send and return successfully
    console.log("Success.");
}).fail(function(){
    // this part will run when an error occurres
    console.log("An error has occurred.");
}).always(function(){
    // this part will always run no matter what
  	console.log("Complete.");
});
Posted by: Guest on November-26-2020
3

ajax data post call in javascript

$.ajax({
   url: 'ajaxfile.php',
   type: 'post',
   data: {name:'yogesh',salary: 35000,email: '[email protected]'},
   success: function(response){

   }
});
Posted by: Guest on October-27-2020
0

js functional ajax requests

function checkUserIdExists(userid, callback) {
        return $.ajax({
        url: 'theurl',
        type: 'GET',
        cache: false,
        data: {
           userid: userid
        }
    })
    .done(callback)
    .fail(function(jqXHR, textStatus, errorThrown) {
        // Handle error
    });
}

checkUserIdExists(2, function(data) {
    console.log(data); // Do what you want with the data returned
});
Posted by: Guest on May-28-2020
0

javascript ajax post

<!DOCTYPE html>
<html>
<body>

<h1>The XMLHttpRequest Object</h1>

<p id="demo">Let AJAX change this text.</p>

<button type="button" onclick="loadDoc()">Change Content</button>

<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  xhttp.open("GET", "ajax_info.txt", false);
  xhttp.send();
  document.getElementById("demo").innerHTML = xhttp.responseText;
}
</script>

</body>
</html>
Posted by: Guest on July-21-2021

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