Answers for "how to post jquery"

23

jquery ajax post example

var formData = {name:"John", surname:"Doe", age:"31"}; //Array 

$.ajax({
    url : "https://example.com/rest/getData", // Url of backend (can be python, php, etc..)
    type: "POST", // data type (can be get, post, put, delete)
    data : formData, // data in json format
  	async : false, // enable or disable async (optional, but suggested as false if you need to populate data afterwards)
    success: function(response, textStatus, jqXHR) {
    	console.log(response);
    },
    error: function (jqXHR, textStatus, errorThrown) {
		console.log(jqXHR);
      	console.log(textStatus);
      	console.log(errorThrown);
    }
});
Posted by: Guest on March-10-2020
1

jquery $.post

// Assign handlers immediately after making the request,
// and remember the jqxhr object for this request
var jqxhr = $.post( "example.php", function() {
  alert( "success" );
})
  .done(function() {
    alert( "second success" );
  })
  .fail(function() {
    alert( "error" );
  })
  .always(function() {
    alert( "finished" );
  });
 
// Perform other work here ...
 
// Set another completion function for the request above
jqxhr.always(function() {
  alert( "second finished" );
});
Posted by: Guest on May-21-2020
2

post method javascript code

const postData = async ( url = '', data = {})=>{
    console.log(data);
      const response = await fetch(url, {
      method: 'POST', 
      credentials: 'same-origin',
      headers: {
          'Content-Type': 'application/json',
      },
     // Body data type must match "Content-Type" header        
      body: JSON.stringify(data), 
    });

      try {
        const newData = await response.json();
        console.log(newData);
        return newData;
      }catch(error) {
      console.log("error", error);
      }
  }
Posted by: Guest on May-10-2020

Code answers related to "Javascript"

Browse Popular Code Answers by Language