fetch api javascript
fetch('http://example.com/movies.json')
.then((response) => {
return response.json();
})
.then((myJson) => {
console.log(myJson);
});fetch api javascript
fetch('http://example.com/movies.json')
.then((response) => {
return response.json();
})
.then((myJson) => {
console.log(myJson);
});vanilla javascript api request
var xhr = new XMLHttpRequest();
xhr.onload = function () {
if (xhr.status >= 200 && xhr.status < 300) {
const users = JSON.parse(xhr.response);
const content = document.getElementById("user_content");
for(let i in users){
let user_name = document.createElement("p");
let text = document.createTextNode(`User ID ${users[i].id}: ${users[i].title}`);
user_name.appendChild(text);
content.appendChild(user_name);
}
} else {
console.log('The request failed!');
}
console.log('This always runs...');
};
xhr.open('GET', 'https://jsonplaceholder.typicode.com/posts');
xhr.send();using apis in javascript
// Create a request variable and assign a new XMLHttpRequest object to it.
var request = new XMLHttpRequest()
// Open a new connection, using the GET request on the URL endpoint
request.open('GET', url, true)
request.onload = function () {
// Begin accessing JSON data here
}
// Send request
request.send()Copyright © 2021 Codeinu
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