Answers for "how to avoid json decode error in php json_decode syntax"

php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Posted by: Guest on July-01-2019

php json decoding as string incorrectly

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Posted by: Guest on November-20-2020

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