Answers for "php json decode object"

PHP
19

php parse json

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson
Posted by: Guest on July-01-2019
0

php json decode

$obj = json_decode("{string:'string'}");
Posted by: Guest on March-08-2021

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