Answers for "$_SERVER['REMOTE_ADDR']; showing local ip"

PHP

1

$_server 'remote_addr' not working properly

if(!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
    $ip_address = $_SERVER['HTTP_X_FORWARDED_FOR'];
} else {
    $ip_address = $_SERVER['REMOTE_ADDR'];
}

Posted by: Guest on September-17-2020

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