Answers for "how to access php variable to copy url in javascript"

PHP
1

php copy url

$file = 'http://3.bp.blogspot.com/-AGI4aY2SFaE/Tg8yoG3ijTI/AAAAAAAAA5k/nJB-mDhc8Ds/s400/rizal001.jpg';
$newfile = '/img/submitted/yoyo.jpg';

if ( copy($file, $newfile) ) {
    echo "Copy success!";
}else{
echo "Copy failed.";
}
Posted by: Guest on January-18-2021

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