Answers for "prepared statement mysqli LIKE"

PHP
2

php mysql prepare query

$stmt = $mysqli->prepare("SELECT * FROM myTable WHERE name = ? AND age = ?");
$stmt->bind_param("si", $_POST['name'], $_POST['age']);
$stmt->execute();
$stmt->close();
Posted by: Guest on February-27-2020
0

mysqli_connect using prepare statement

$stmt = $mysqli->prepare("UPDATE myTable SET name = ? WHERE id = ?");
$stmt->bind_param("si", $_POST['name'], $_SESSION['id']);
$stmt->execute();
$stmt->close();
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Posted by: Guest on May-20-2020

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