Answers for "php covert object to json"

PHP
15

json php

//Json Encode

$person = array( 
    "name" => "KINGASV", 
    "title" => "CTO"
); 
$personJSON=json_encode($person);//returns JSON string

//Json Decode

$personJSON = '{"name":"KINGASV","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // KINGASV
Posted by: Guest on July-16-2020
5

php return json

header('Content-type: application/json');
echo json_encode($array);
Posted by: Guest on March-20-2020

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