php declare(strict_types=1)
"Strict types" mode only checks types at specific points in the code; it does not track everything that happens to the variable. Specifically, it checks: the parameters given to the function, if type hints are included in the signature; here you are giving two ints to a function expecting two ints, so there is no error the return value of the function, if a return type hint is included in the signature; here you have no type hint, but if you had a hint of : int, there would still be no error, because the result of $a + $b + $c is indeed an int. Here are some examples that do give errors: declare(strict_types=1); $a = '1'; $b = '2'; function FunctionName(int $a, int $b) { return $a + $b; } echo FunctionName($a, $b);
