Answers for "how to show online images in php array"

PHP
1

Extract images from a folder in php

<?php
function rasmname(){
 $dirname = "./";
 $images = glob($dirname."*.jpg");
foreach($images as $image) {
 echo '<img src="'.$image.'" /><br />';
  }
}
rasmname();
Posted by: Guest on August-08-2020
0

php list output images in a directory

<?php

echo scanDirectoryImages("uploads");

/**
* Recursively search through directory for images and display them
* 
* @param  array  $exts
* @param  string $directory
* @return string
*/
function scanDirectoryImages($directory, array $exts = array('jpeg', 'jpg', 'gif', 'png'))
{
if (substr($directory, -1) == '/') {
    $directory = substr($directory, 0, -1);
}
$html = '';
if (
    is_readable($directory)
    && (file_exists($directory) || is_dir($directory))
) {
    $directoryList = opendir($directory);
    while($file = readdir($directoryList)) {
        if ($file != '.' && $file != '..') {
            $path = $directory . '/' . $file;
            if (is_readable($path)) {
                if (is_dir($path)) {
                    return scanDirectoryImages($path, $exts);
                }
                if (
                    is_file($path)
                    && in_array(end(explode('.', end(explode('/', $path)))),   $exts)
                ) {
                    $html .= '<a href="' . $path . '"><img src="' . $path
                        . '" style="max-height:100px;max-width:100px" />  </a>';
                }
            }
        }
    }
    closedir($directoryList);
}
return $html;
}
Posted by: Guest on December-19-2019

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