Answers for "json decode array of objects php"

php decode json object

<?php

$json = '{"firstName":"Peter","lastName:":"Silva","age":23}';

$personInfo = json_decode(json);

echo $personInfo->age;

?>

Posted by: Guest on October-22-2020

php json decode

$obj = json_decode("{string:'string'}");

Posted by: Guest on March-08-2021

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