Answers for "php debug console"

PHP
1

console.log in php

/*
console.log in php
*/

<?php
	function consoleLog($message) {
		echo '<script type="text/javascript">' .
          'console.log(' . $message . ');</script>';
	}

	consoleLog('Hello, greppers!');
?>
Posted by: Guest on May-11-2020
2

console php

//display message in console

<?php
	function console_log($msg) {
		echo '<script>' .
          'console.log("'.$msg .' ")</script>';
	}

	console_log("Hi there!");
?>
Posted by: Guest on October-06-2020
2

debug php

// ------ string -------
// use echo, exit for output
$a = 123
echo ($a);
exit;


// ------ array -------
$array = array(
	1 => 'apple',
  	2 => 'banana',
)

// Method 1
echo "<pre>";
print_r($array);
echo "</pre>";

// Method 2 
echo "<pre>";
var_dump($array);
echo "</pre>";

// Method 3 (no need exit) beacause of dd is already exit
dd($array)
  
// Method 4 (cakephp)
pr ($array);


// ------ json -------
$json = {"a":"123"}

pr (json_encode($json));
exit;

print_r (json_encode($json));
exit;
Posted by: Guest on October-11-2020
-1

php print to console

<script>
    console.log(<?= json_encode($foo); ?>);
</script>
Posted by: Guest on June-06-2020
1

console_log in php

<?php
function console_log($output, $with_script_tags = true) {
    $js_code = 'console.log(' . json_encode($output, JSON_HEX_TAG) . 
');';
    if ($with_script_tags) {
        $js_code = '<script>' . $js_code . '</script>';
    }
    echo $js_code;
}
Posted by: Guest on August-12-2020
0

php console print

$a = array(
 null => 'a',
 true => 'b',
 false => 'c',
 0 => 'd',
 1 => 'e',
 '' => 'f'
);

echo count($a), "\n";
Posted by: Guest on October-10-2020

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