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Answers for "calculate days difference between two dates in php"

PHP
18

php calculate date difference

//get Date diff as intervals 
$d1 = new DateTime("2018-01-10 00:00:00");
$d2 = new DateTime("2019-05-18 01:23:45");
$interval = $d1->diff($d2);
$diffInSeconds = $interval->s; //45
$diffInMinutes = $interval->i; //23
$diffInHours   = $interval->h; //8
$diffInDays    = $interval->d; //21
$diffInMonths  = $interval->m; //4
$diffInYears   = $interval->y; //1

//or get Date difference as total difference
$d1 = strtotime("2018-01-10 00:00:00");
$d2 = strtotime("2019-05-18 01:23:45");
$totalSecondsDiff = abs($d1-$d2); //42600225
$totalMinutesDiff = $totalSecondsDiff/60; //710003.75
$totalHoursDiff   = $totalSecondsDiff/60/60;//11833.39
$totalDaysDiff    = $totalSecondsDiff/60/60/24; //493.05
$totalMonthsDiff  = $totalSecondsDiff/60/60/24/30; //16.43
$totalYearsDiff   = $totalSecondsDiff/60/60/24/365; //1.35
Posted by: Guest on November-01-2019
0

how to calculate days between two dates in php

<?php
function dateDifference($start_date, $end_date)
{
    // calulating the difference in timestamps 
    $diff = strtotime($start_date) - strtotime($end_date);
     
    // 1 day = 24 hours 
    // 24 * 60 * 60 = 86400 seconds
    return ceil(abs($diff / 86400));
}
 
// start date 
$start_date = "2016-01-02";
 
// end date 
$end_date = "2016-01-21";
 
// call dateDifference() function to find the number of days between two dates
$dateDiff = dateDifference($start_date, $end_date);
 
echo "Difference between two dates: " . $dateDiff . " Days ";
?>
Posted by: Guest on August-08-2020
0

Calculate the Difference Between Two Dates Using PHP

phpCopy$firstDate = "2019-01-01";
$secondDate = "2020-03-04";

$dateDifference = abs(strtotime($secondDate) - strtotime($firstDate));

$years  = floor($dateDifference / (365 * 60 * 60 * 24));
$months = floor(($dateDifference - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
$days   = floor(($dateDifference - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 *24) / (60 * 60 * 24));

echo $years." year,  ".$months." months and ".$days." days";

//output: 1 year, 2 months and 3 days
Posted by: Guest on April-23-2021

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