Answers for "php difference between two date"

PHP

php calculate date difference

//get Date diff as intervals 
$d1 = new DateTime("2018-01-10 00:00:00");
$d2 = new DateTime("2019-05-18 01:23:45");
$interval = $d1->diff($d2);
$diffInSeconds = $interval->s; //45
$diffInMinutes = $interval->i; //23
$diffInHours   = $interval->h; //8
$diffInDays    = $interval->d; //21
$diffInMonths  = $interval->m; //4
$diffInYears   = $interval->y; //1

//or get Date difference as total difference
$d1 = strtotime("2018-01-10 00:00:00");
$d2 = strtotime("2019-05-18 01:23:45");
$totalSecondsDiff = abs($d1-$d2); //42600225
$totalMinutesDiff = $totalSecondsDiff/60; //710003.75
$totalHoursDiff   = $totalSecondsDiff/60/60;//11833.39
$totalDaysDiff    = $totalSecondsDiff/60/60/24; //493.05
$totalMonthsDiff  = $totalSecondsDiff/60/60/24/30; //16.43
$totalYearsDiff   = $totalSecondsDiff/60/60/24/365; //1.35

Posted by: Guest on November-01-2019

php get day diff

$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;

echo round($datediff / (60 * 60 * 24));

Posted by: Guest on April-22-2020

Source

date diff php

$datetime1 	= new DateTime('2020-10-11 16:52:52');
$datetime2 	= new DateTime('2020-10-13 16:52:52');
$interval 	= $datetime1->diff($datetime2);

echo $interval->format('%a days');

Posted by: Guest on June-26-2020

php get date between two dates

$period = new DatePeriod(
     new DateTime('2010-10-01'),
     new DateInterval('P1D'),
     new DateTime('2010-10-05')
);

//Which should get you an array with DateTime objects. 

//To iterate

foreach ($period as $key => $value) {
    //$value->format('Y-m-d')       
}

Posted by: Guest on August-22-2020

Calculate the Difference Between Two Dates Using PHP

phpCopy$firstDate = "2019-01-01";
$secondDate = "2020-03-04";

$dateDifference = abs(strtotime($secondDate) - strtotime($firstDate));

$years  = floor($dateDifference / (365 * 60 * 60 * 24));
$months = floor(($dateDifference - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
$days   = floor(($dateDifference - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 *24) / (60 * 60 * 24));

echo $years." year,  ".$months." months and ".$days." days";

//output: 1 year, 2 months and 3 days

Posted by: Guest on April-23-2021

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