function return time ago php
public function convert_time_to_days($date) { $current_date = date("Y-m-d H:m:s"); $time = array(); $day = floor((strtotime($current_date) - strtotime($date)) / (60 * 60 * 24)); if ($day == 0) { $hour = floor((strtotime($current_date) - strtotime($date)) / (60 * 60)); if ($hour == 0) { $minute = floor((strtotime($current_date) - strtotime($date)) / (60)); $time = $minute . __d('course', "minutes ago"); } else { $time = $hour . __d('course', "hours ago"); } } else { $time = $day . __d('course', "days ago"); } return $time; }