throwing an exception python
raise Exception("message")try except python
try:
print("I will try to print this line of code")
except:
print("I will print this line of code if an error is encountered")catch error python
import traceback
dict = {'a':3,'b':5,'c':8}
try:
print(dict[q])
except:
traceback.print_exc()
# This will trace you back to the line where everything went wrong.
# So in this case you will get back line 5python catch exception
try:
# Code to test / execute
print('Test')
except (SyntaxError, IndexError) as E: # specific exceptions
# Code in case of SyntaxError for example
print('Synthax or index error !')
except :
# Code for any other exception
print('Other error !')
else:
# Code if no exception caught
print('No error')
finally:
# Code executed after try block (success) or any exception (ie everytime)
print('Done')
# This code is out of try / catch bloc
print('Anything else')catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')python catch any exception
try:
do_something()
except:
print "Caught it!"Copyright © 2021 Codeinu
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