exception pyton print
except Exception as e: print(e)exception pyton print
except Exception as e: print(e)catch error python
import traceback
dict = {'a':3,'b':5,'c':8}
try:
print(dict[q])
except:
traceback.print_exc()
# This will trace you back to the line where everything went wrong.
# So in this case you will get back line 5try catch in python
try:
print("try to run this block")
except:
print("run this bock if there was error in earlier block")error handling Pyhtin
# taking input from the user
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
print('bye')
# if you wanna ask their age until they enter the correct number use While Loop
while True:
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
else:
breakCopyright © 2021 Codeinu
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