get index of list python
list.index(element)get index of list python
list.index(element)python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find index of first matching element in a list
# Basic syntax:
list.index(element, start, end)
# Where:
# - Element is the item you're looking for in the list
# - Start is optional, and is the list index you want to start at
# - End is option, and is the list index you want to stop searching at
# Note, Python is 0-indexed
# Example usage:
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 42, 9, 10]
my_list.index(42)
--> 8python index of element in list
# alphabets list
alphabets = ['a', 'e', 'i', 'o', 'g', 'l', 'i', 'u']
# index of 'i' in alphabets
index = alphabets.index('i') # 2
print('The index of i:', index)
# 'i' after the 4th index is searched
index = alphabets.index('i', 4) # 6
print('The index of i:', index)
# 'i' between 3rd and 5th index is searched
index = alphabets.index('i', 3, 5) # Error!
print('The index of i:', index)Finding index of an item list
>>> ["foo", "bar", "baz"].index("bar")
1find index of elem list python
# Find index position of first occurrence of 'Ok' in the list
indexPos = listOfElems.index('Ok')
print('First index of element "Ok" in the list : ', indexPos)Copyright © 2021 Codeinu
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