Answers for "python sys.argv"

python get command line arguments

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

python read arguments

#!/usr/bin/python

import sys

print('Number of arguments:', len(sys.argv), 'arguments.')
print('Argument List:', str(sys.argv))

python sys.argv

def add(a, b):
  return a + b

"""
You need to execute the script add.py as follows:
'python add.py 5 2'
The 'sys.argv[0]' is the name of your script,
so you need to get the second and the third one.
"""

print(add(int(sys.argv[1]), int(sys.argv[2])))

"""
With the command: 'python add.py 5 2',
this python script will returns 7
"""

python sys.argv exception

try:
    filename = sys.argv[1]
except IndexError:
    print "You did not specify a file"
    sys.exit(1)

how to take a list as input in python using sys.srgv

argv = sys.argv[1:]

argv in python

#argv in python


import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

#command in cmd :
$ python test.py arg1 arg2 arg3

# producing following result :
Number of arguments: 4 arguments.
Argument List: ['test.py', 'arg1', 'arg2', 'arg3']