find the sum of all the multiples of 3 or 5 below 1000 python
nums = [3, 5]
result = 0
for i in range(0,1000):
if i%3 == 0 or i%5 == 0:
result += i
print(result)find the sum of all the multiples of 3 or 5 below 1000 python
nums = [3, 5]
result = 0
for i in range(0,1000):
if i%3 == 0 or i%5 == 0:
result += i
print(result)sum of multiples of 3 or 5 python
total = []
for num in range(0,1001):
if (num % 3 == 0) or (num % 5 == 0):
total.append(num)
print(sum(total))Sum of all the multiples of 3 or 5
const findSum = n => {
let countArr = []
for(let i = 0; i <= n; i++) if(i % 3 === 0 || i % 5 === 0) countArr.push(i)
return countArr.reduce((acc , curr) => acc + curr)
}
console.log(findSum(5))Sum of all the multiples of 3 or 5
const findSum = n => {
let countArr = []
for(let i = 0; i <= n; i++) countArr.push(i)
let finalArr = countArr.map(digit => {
if(digit % 3 === 0 || digit % 5 === 0) return digit
else return 0
}).reduce((acc , curr) => acc + curr)
return finalArr
}
console.log(findSum(10))Copyright © 2021 Codeinu
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