max of a dict
dic={0: 1.4984074067880424, 1: 1.0984074067880423, 2: 1.8984074067880425, 3: 2.2984074067880425, 4: 2.2984074067880425}
max_value = max(dic.values()) # maximum value
max_keys = [k for k, v in dic.items() if v == max_value] # getting all keys containing the `maximum`
print(max_value, max_keys)find the max value in dictionary python
my_dict = {'a': 5, 'b': 10, 'c': 6, 'd': 12, 'e': 7}
max(my_dict, key=my_dict.get) # returns 'd'max element in dictionary python
import operator
stats = {'a':1000, 'b':3000, 'c': 100}
max(stats.iteritems(), key=operator.itemgetter(1))[0]get max n values in dict py
import heapq
from operator import itemgetter
n = 3
items = {'a': 7, 'b': 12, 'c': 9, 'd': 0, 'e': 24, 'f': 10, 'g': 24}
topitems = heapq.nlargest(n, items.items(), key=itemgetter(1)) # Use .iteritems() on Py2
topitemsasdict = dict(topitems)Copyright © 2021 Codeinu
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