python counter nested dictionary
import collections
a = collections.defaultdict(collections.Counter)
inf = [('fruit','apple'),('car','truck'),('fruit','banana'),('fruit','banana')]
for category,item in inf:
a[category][item] = a[category][item] + 1
#print(a)
#{'fruit': Counter({'banana': 2, 'apple': 1}), 'car': Counter({'truck': 1})})Nested dictionary Python
IDs = ['emp1','emp2','emp3']
EmpInfo = [{'name': 'Bob', 'job': 'Mgr'},
{'name': 'Kim', 'job': 'Dev'},
{'name': 'Sam', 'job': 'Dev'}]
D = dict(zip(IDs, EmpInfo))
print(D)
# Prints {'emp1': {'name': 'Bob', 'job': 'Mgr'},
# 'emp2': {'name': 'Kim', 'job': 'Dev'},
# 'emp3': {'name': 'Sam', 'job': 'Dev'}}python create nested dictionary
nested_dict = { 'dictA': {'key_1': 'value_1'},
'dictB': {'key_2': 'value_2'}}python get nested dictionary keys
example_dict.get('key1', {}).get('key2')nested dictionary python
people = {1: {'name': 'John', 'age': '27', 'sex': 'Male'},
2: {'name': 'Marie', 'age': '22', 'sex': 'Female'}}
people[3] = {}
people[3]['name'] = 'Luna'
people[3]['age'] = '24'
people[3]['sex'] = 'Female'
people[3]['married'] = 'No'
print(people[3])
#Output:
# {'name': 'Luna', 'age': '24', 'sex': 'Female', 'married': 'No'}Nested dictionary Python
D = {'emp1': {'name': 'Bob', 'job': 'Mgr'},
'emp2': {'name': 'Kim', 'job': 'Dev'},
'emp3': {'name': 'Sam', 'job': 'Dev'}}Copyright © 2021 Codeinu
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