recursion
print("Hello World")
recursion
int function(int value) {
if(value < 1)
return;
function(value - 1);
printf("%d ",value);
}
recursion
# modified code tranclated to python from (Drab Duck)
def fact(num):
if num <= 1:
return 1
else:
return num*fact(num-1)
recursion
/*Java*/
static void recursion(){ recursion(0); }
static void recursion(int x){
System.out.println("eheh " + x);
if(x != 666) recursion(x+1);
}
recursion
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Recursion
/**
* Return all subsequences of word (as defined above) separated by commas,
* with partialSubsequence prepended to each one.
*/
private static String subsequencesAfter(String partialSubsequence, String word) {
if (word.isEmpty()) {
// base case
return partialSubsequence;
} else {
// recursive step
return subsequencesAfter(partialSubsequence, word.substring(1))
+ ","
+ subsequencesAfter(partialSubsequence + word.charAt(0), word.substring(1));
}
}
recursion
function loop(x) {
if (x >= 10) // "x >= 10" is the exit condition (equivalent to "!(x < 10)")
return;
// do stuff
loop(x + 1); // the recursive call
}
loop(0);
recursion
#https://github.com/aspittel/coding-cheat-sheets/blob/master/fundamentals/recursion.md
def factorial(n):
if n <= 1:
return 1
return n * factorial(n - 1)
# Memoization
# Memoization is often useful in recursion. This is when the results of a function call are remembered so they can be used again in later function calls. This is like caching your results to use again.
# Code Example
factorial_memo = {}
def factorial(n):
if n <= 1:
return 1
elif n not in factorial_memo:
factorial_memo[n] = n * factorial(n-1)
return factorial_memo[n]
# Tail Recursion
# Tail recursion is where calculations are performed first and then the recursive call is executed. Some programming languages, usually functional ones, optimize tail calls so they take up less room on the call stack.
def factorial(n, running_total=1):
if n <= 1:
return running_total
return factorial(n-1, n * running_total)
recursion
def is_divisible(x, y):
if x % y == 0:
return True
else:
return False
def is_power(a, b):
if a == 1 or b == 1: # a more succinct way to test base case
return a == 1
return is_divisible(a, b) and is_power(a/b, b) # divisible and recursions report True?
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