Answers for "kwargs in python"

unlimited arguments python

def add(*args):		# *args takes multiple inputs
  return sum(args)


print(add(1,2,3,4,5))    # prints 15
print(add(10, 20, 30))	 # prints 60

args kwargs python

>>> def argsKwargs(*args, **kwargs):
...     print(args)
...     print(kwargs)
... 
>>> argsKwargs('1', 1, 'slgotting.com', upvote='yes', is_true=True, test=1, sufficient_example=True)
('1', 1, 'slgotting.com')
{'upvote': 'yes', 'is_true': True, 'test': 1, 'sufficient_example': True}

variable number of arguments to python class

def multiply(*args):
    z = 1
    for num in args:
        z *= num
    print(z)

multiply(4, 5)
multiply(10, 9)
multiply(2, 3, 4)
multiply(3, 5, 10, 6)

difference between args and kwargs in python

# We use *args and **kwargs as an argument when we are unsure 
# about the number of arguments to pass in the functions.

#This is an example of *args 
def adder(*num):
    sum = 0
    
    for n in num:
        sum = sum + n

    print("Sum:",sum)

adder(3,5)
adder(4,5,6,7)
adder(1,2,3,5,6)\


#This is an example of **kwargs
def intro(**data):
    print("\nData type of argument:",type(data))

    for key, value in data.items():
        print("{} is {}".format(key,value))

intro(Firstname="Sita", Lastname="Sharma", Age=22, Phone=1234567890)
intro(Firstname="John", Lastname="Wood", Email="[email protected]", Country="Wakanda", Age=25, Phone=9876543210)

kwargs in python

def display2(a,b,c):
    print("kwarg1:", a)
    print("kwarg2:", b)
    print("kwarg3:", c)

d = {"a": 1, "b": 2, "c": 3}
display2(**d)

kwargs in python

def display(**kwargs):
    d = {k.upper():v.upper() for k,v in kwargs.items() }
    return d
   
d = {"name":"neo","age":"33","city":"tokyo"}
print(display(**d))