checking if a value is in a set python
thisset = {"apple", "banana", "cherry"}
if "apple" in thisset:
print("Yes, 'apple' is in this set")checking if a value is in a set python
thisset = {"apple", "banana", "cherry"}
if "apple" in thisset:
print("Yes, 'apple' is in this set")python sets
# You can't create a set like this in Python
my_set = {} # ---- This is a Dictionary/Hashmap
# To create a empty set you have to use the built in method:
my_set = set() # Correct!
set_example = {1,3,2,5,3,6}
print(set_example)
# OUTPUT
# {1,3,2,5,6} ---- Sets do not contain duplicates and are unorderedpython set &
>>> A = {0, 2, 4, 6, 8};
>>> B = {1, 2, 3, 4, 5};
>>> print("Union :", A | B)
Union : {0, 1, 2, 3, 4, 5, 6, 8}
>>> print("Intersection :", A & B)
Intersection : {2, 4}
>>> print("Difference :", A - B)
Difference : {0, 8, 6}
# elements not present both sets
>>> print("Symmetric difference :", A ^ B)
Symmetric difference : {0, 1, 3, 5, 6, 8}python set
set_example = {1, 2, 3, 4, 5, 5, 5}
print(set_example)
# OUTPUT
# {1, 2, 3, 4, 5} ----- Does not print repetitionspython set contains
a_set = {1, 2, 3}
one_in_a_set = 1 in a_set # TrueCopyright © 2021 Codeinu
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