python get command line arguments
import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))
#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']import argv python
from sys import argv
print(argv)how to take a list as input in python using sys.srgv
argv = sys.argv[1:]argv in python
#argv in python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
#command in cmd :
$ python test.py arg1 arg2 arg3
# producing following result :
Number of arguments: 4 arguments.
Argument List: ['test.py', 'arg1', 'arg2', 'arg3']argv python function
# arguments
def test_var_args(f_arg, *argv):
print("first normal arg:", f_arg)
for arg in argv:
print("another arg through *argv :", arg)
test_var_args('yasoob','python','eggs','test')
# keywork arguments
def test_var_kwargs(f_arg, **kwargs):
print(f_arg)
for (key, item) in kwargs.items():
print("Keyword: ", key)
print("Value: ", item)
test_var_kwargs('yasoob', x = 12)Copyright © 2021 Codeinu
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