iterative binary search python
def binary_search(a, key):
low = 0
high = len(a) - 1
while low < high:
mid = (low + high) // 2
if key == a[mid]:
return True
elif key < mid:
high = mid - 1
else:
low = mid + 1
return Falseiterative binary search python
def binary_search(a, key):
low = 0
high = len(a) - 1
while low < high:
mid = (low + high) // 2
if key == a[mid]:
return True
elif key < mid:
high = mid - 1
else:
low = mid + 1
return FalseImplement a binary search of a sorted array of integers Using pseudo-code.
# Here's the pseudocode for binary search, modified for searching in an array. The inputs are the array, which we call array; the number n of elements in array; and target, the number being searched for. The output is the index in array of target:
1.Let min = 0 and max = n-1.
2. Compute guess as the average of max and min, rounded down (so that it is an integer).
3. If array[guess] equals target, then stop. You found it! Return guess.
4. If the guess was too low, that is, array[guess] < target, then set min = guess + 1.
5. Otherwise, the guess was too high. Set max = guess - 1.
6. Go back to step 2.Copyright © 2021 Codeinu
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