defaultdict python

python ordereddict

>>> # regular unsorted dictionary
>>> d = {'banana': 3, 'apple': 4, 'pear': 1, 'orange': 2}

>>> # dictionary sorted by key
>>> OrderedDict(sorted(d.items(), key=lambda t: t[0]))
OrderedDict([('apple', 4), ('banana', 3), ('orange', 2), ('pear', 1)])

>>> # dictionary sorted by value
>>> OrderedDict(sorted(d.items(), key=lambda t: t[1]))
OrderedDict([('pear', 1), ('orange', 2), ('banana', 3), ('apple', 4)])

>>> # dictionary sorted by length of the key string
>>> OrderedDict(sorted(d.items(), key=lambda t: len(t[0])))
OrderedDict([('pear', 1), ('apple', 4), ('orange', 2), ('banana', 3)])

Posted by: Guest on April-01-2020

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>>> s = [('yellow', 1), ('blue', 2), ('yellow', 3), ('blue', 4), ('red', 1)] >>> d = defaultdict(list) >>> for k, v in s: ... d[k].append(v) ... >>> d.items() [('blue', [2, 4]), ('red', [1]), ('yellow', [1, 3])]

>>> from collections import defaultdict >>> ice_cream = defaultdict(lambda: 'Vanilla') >>> >>> ice_cream = defaultdict(lambda: 'Vanilla') >>> ice_cream['Sarah'] = 'Chunky Monkey' >>> ice_cream['Abdul'] = 'Butter Pecan' >>> print ice_cream['Sarah'] Chunky Monkey >>> print ice_cream['Joe'] Vanilla >>>

>>> # Tally occurrences of words in a list >>> cnt = Counter() >>> for word in ['red', 'blue', 'red', 'green', 'blue', 'blue']: ... cnt[word] += 1 >>> cnt Counter({'blue': 3, 'red': 2, 'green': 1}) >>> # Find the ten most common words in Hamlet >>> import re >>> words = re.findall(r'\w+', open('hamlet.txt').read().lower()) >>> Counter(words).most_common(10) [('the', 1143), ('and', 966), ('to', 762), ('of', 669), ('i', 631), ('you', 554), ('a', 546), ('my', 514), ('hamlet', 471), ('in', 451)]

>>> from collections import defaultdict >>> food_list = 'spam spam spam spam spam spam eggs spam'.split() >>> food_count = defaultdict(int) # default value of int is 0 >>> for food in food_list: ... food_count[food] += 1 # increment element's value by 1 ... defaul

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