Answers for "py - count if a word is present in a column"

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py - count if a word is present in a column

words = 'one two three'.split()

df.assign(counts=df.texts.str.count('|'.join(words)))

        texts  counts
0  throne one       2
1     bar one       1
2     foo two       1
3   bar three       1
4     foo two       1
5     bar two       1
6     foo one       1
7   foo three       1
8   one three       2

Posted by: Guest on March-19-2021

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