get next iterator without incrementing python
from more_itertools import peekable
p = peekable(['a', 'b'])
p.peek()
# 'a'
next(p)
# 'a'
p.peek()
# 'b'get next iterator without incrementing python
from more_itertools import peekable
p = peekable(['a', 'b'])
p.peek()
# 'a'
next(p)
# 'a'
p.peek()
# 'b'Copyright © 2021 Codeinu
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