find kth max and min element in an array
#include <bits/stdc++.h>
using namespace std;
int main(){
const int size = 10;
int k = 3; //Can be any number smalled than size
int array[size] = {5,2,8,34,73,82,1,6,19,29};
sort(array,array+size);
int smallestKthElement = array[k-1];
int largestKthElement = array[size-k];
}Minimum and maximum element in an Array
def divideAndConquer_Max(arr, ind, len):
maximum = -1;
if (ind >= len - 2):
if (arr[ind] > arr[ind + 1]):
return arr[ind];
else:
return arr[ind + 1];
maximum = divideAndConquer_Max(arr, ind + 1, len);
if (arr[ind] > maximum):
return arr[ind];
else:
return maximum;
def divideAndConquer_Min(arr, ind, len):
minimum = 0;
if (ind >= len - 2):
if (arr[ind] < arr[ind + 1]):
return arr[ind];
else:
return arr[ind + 1];
minimum = divideAndConquer_Min(arr, ind + 1, len);
if (arr[ind] < minimum):
return arr[ind];
else:
return minimum;
if __name__ == '__main__':
minimum, maximum = 0, -1;
# array initialization
arr = [6, 4, 8, 90, 12, 56, 7, 1, 63];
maximum = divideAndConquer_Max(arr, 0, 9);
minimum = divideAndConquer_Min(arr, 0, 9);
print("The minimum number in the array is: ", minimum);
print("The maximum number in the array is: ", maximum);find minimum and maximum element in an array
#In python
#List
myListName = ["value", 3, 3.1, "a", True]
minimumValue = min(myListName)
maximumValue = max(myListName)
#Numpy array
import numpy as np
myListName = ["value", 3, 3.1, "a", True]
myArrayName = np.array(myListName)
minimumValue = min(myArrayName)
maximumValue = max(myArrayName)Find Minimum array
Array -- Find Minimum
Write a method that can find the maximum number from an int Array
Solution 1:
public static void main(String[] args) {
int[] arr = new int[]{2,4,6,8,20};
System.out.println(maxValue(arr));
public static int maxValue( int[] n ) {
int min = Integer.MAX_VALUE;
for(int each: n)
if(each < min)
min = each;
return min;
}
Solution 2:
public static int maxValue( int[] n ) {
Arrays.sort( n );
return n [ 0 ];
}Copyright © 2021 Codeinu
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