Answers for "pivot table with lambda"

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pivot table with lambda

pct_75 = lambda y: np.percentile(y, 75)
pct_75 .__name__ = 'pct_75 '

pct_25 = lambda y: np.percentile(y, 25)
pct_25 .__name__ = 'pct_25'
Posted by: Guest on July-17-2020

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