Group the values for each key in the RDD into a single sequence.
rdd = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
sorted(rdd.groupByKey().mapValues(len).collect())
# [('a', 2), ('b', 1)]
sorted(rdd.groupByKey().mapValues(list).collect())
# [('a', [1, 1]), ('b', [1])]Copyright © 2021 Codeinu
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