Answers for "python remove duplicates from list of dict"

removing duplicates from dictionary python

student_data = {'id1': 
   {'name': ['Sara'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
 'id2': 
  {'name': ['David'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
 'id3': 
    {'name': ['Sara'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
 'id4': 
   {'name': ['Surya'], 
    'class': ['V'], 
    'subject_integration': ['english, math, science']
   },
}

result = {}

for key,value in student_data.items():
    if value not in result.values():
        result[key] = value

print(result)

python remove repeated elements from list

# ----- Create a list with no repeating elements ------ #

mylist = [67, 7, 89, 7, 2, 7]
newlist = []

  for i in mylist: 
    if i not in newlist: 
        newlist.append(i)

python remove duplicates from list of dict

# set the dict to a tuple for hashability, then use {} for set literal and retrn each item to dict. 
[dict(t) for t in {tuple(d.items()) for d in l}]
# using two maps()
list(map(lambda t: dict(t), set(list(map(lambda d: tuple(d.items()), l)))))

python dict remove duplicates where name are not the same

import itertools
mylist = [{'x':2020 , 'y':20},{'x':2020 , 'y':30},{'x':2021 , 'y':10},{'x':2021 , 'y':5}]
mylist1=[]
for key, group in itertools.groupby(mylist,lambda x:x["x"]):
    max_y=0
    for thing in group:
        max_y=max(max_y,thing["y"])
    mylist1.append({"x":key,"y":max_y})
print(mylist1)