Return the intersection of this RDD and another one
rdd1 = sc.parallelize([1, 10, 2, 3, 4, 5])
rdd2 = sc.parallelize([1, 6, 2, 3, 7, 8])
rdd1.intersection(rdd2).collect()
# [1, 2, 3]Return the intersection of this RDD and another one
rdd1 = sc.parallelize([1, 10, 2, 3, 4, 5])
rdd2 = sc.parallelize([1, 6, 2, 3, 7, 8])
rdd1.intersection(rdd2).collect()
# [1, 2, 3]Copyright © 2021 Codeinu
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