Answers for "python 3 define type in arguments with default value"

python default arguments

def my_function(name, age = 20):
  print(name + " is " + str(age) + " years old"

my_function("Mitro") # Mitro is 20 years old
my_function("Mitro", 26) #Mitro is 26 years old

python default arguments

def your_function(arg,kwarg='default'):
    return arg + kwarg

python 3 define type in arguments with default value

def foo(opts: dict = {}):
    pass

print(foo.__annotations__)