Answers for "secant method numpy"

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secant method numpy

def Newton(f, dfdx, x, eps):
    f_value = f(x)
    iteration_counter = 0
    while abs(f_value) > eps and iteration_counter < 100:
        try:
            x = x - float(f_value)/dfdx(x)
        except ZeroDivisionError:
            print "Error! - derivative zero for x = ", x
            sys.exit(1)     # Abort with error

        f_value = f(x)
        iteration_counter += 1

    # Here, either a solution is found, or too many iterations
    if abs(f_value) > eps:
        iteration_counter = -1
    return x, iteration_counter

def f(x):
    return x**2 - 9

def dfdx(x):
    return 2*x

solution, no_iterations = Newton(f, dfdx, x=1000, eps=1.0e-6)

if no_iterations > 0:    # Solution found
    print "Number of function calls: %d" % (1 + 2*no_iterations)
    print "A solution is: %f" % (solution)
else:
    print "Solution not found!"
Posted by: Guest on September-24-2020

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