python remove by index
a = [0, 1, 2, 3, 4, 5]
el = a.pop(2)python remove nth element from list
def drop_nth_element_in_list(_list : list, drop_step: int):
result_list = _list.copy()
counter = 0
if drop_step <= 1:
return []
for element in _list:
counter += 1
if counter == drop_step:
result_list.remove(element)
counter = 0
return result_listCopyright © 2021 Codeinu
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