Given a list of ints, return True if the array contains a 3 next to a 3 somewhere.
def has_33(x):
for i in range(len(x)-1):
if x[i:i+2] == [3,3]:
return True
else:
return FalseGiven a list of ints, return True if the array contains a 3 next to a 3 somewhere.
def has_33(x):
for i in range(len(x)-1):
if x[i:i+2] == [3,3]:
return True
else:
return FalseCopyright © 2021 Codeinu
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