Answers for "rotation of n prime numbers in python"

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rotation of n prime numbers in python

def rotate(n1):
        l=len(str(n1))
        a=n1%10
        n1=n1//10
        n1=(pow(10,l-1)*a)+n1
        return n1
def prime(n2):
      count=0
      for i in range(1,n2):
          if(n2%i==0):
              count+=1
          if(count>1):
            return False
        else:
            return True
l=len(str(num))
i=1
while(i<=l):
    if(prime(num)):
         num=rotate(num)
     else:
         return False
     i+=1
return True
Posted by: Guest on October-04-2020

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