python range in intervals of 10
print("using start, stop, and step arguments in Python range() function")
print("Printing All odd numbers between 1 and 10 using range()")
for i in range(1, 10, 2):
print(i, end=', ')python range in intervals of 10
print("using start, stop, and step arguments in Python range() function")
print("Printing All odd numbers between 1 and 10 using range()")
for i in range(1, 10, 2):
print(i, end=', ')python range
# range(start, stop, step)
# start = (can be ommitted) index to begin at (INCLUSIVE)
# stop = generate numbers up to, but not including this number (EXCLUSIVE)
# step = (can be omitted) difference between each number in the sequence
# idx: 0 1 2 3 4
# arr: 19 5 3 22 13
arr = [19,5,3,22,13]
# range(stop)
for i in range(len(arr)):
print(arr[i]) # prints: 19, 5, 3, 22, 13
# range(start, stop)
for i in range(2, len(arr)):
print(arr[i]) # prints: 3, 22, 13
# range(start, stop, step)
for i in range(0, len(arr), 2):
print(arr[i]) # prints: 19, 3, 13
# reverse:
for i in range(len(arr)-1, -1, -1):
print(arr[i])range(n,n) python
# if numbers are same in the range function then,
# the range function outputs empty range
# this is because, there are no integers b/w n and n
for i in range(1,1):
print("runs")
# prints nothingrange python start at 1
>>> def range1(start, end):
... return range(start, end+1)
...
>>> range1(1, 10)
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]Copyright © 2021 Codeinu
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