how to get median mode average of a python list
>>> import statistics
>>> statistics.median([3, 5, 1, 4, 2])
3
>>> statistics.median([3, 5, 1, 4, 2, 6])
3.5how to get median mode average of a python list
>>> import statistics
>>> statistics.median([3, 5, 1, 4, 2])
3
>>> statistics.median([3, 5, 1, 4, 2, 6])
3.5calculate mode in python
# Calculating the mode when the list of numbers may have multiple modes
from collections import Counter
def calculate_mode(n):
c = Counter(n)
num_freq = c.most_common()
max_count = num_freq[0][1]
modes = []
for num in num_freq:
if num[1] == max_count:
modes.append(num[0])
return modes
# Finding the Mode
def calculate_mode(n):
c = Counter(n)
mode = c.most_common(1)
return mode[0][0]
#src : Doing Math With Python.statistics mode python when no.s are same
import statistics
statistics.mode(x) #mean and median are also available.python finding mode of a list
import random
numbers = []
limit = int(input("Please enter how many numbers you would like to compare:\n"))
mode =0
for i in range(0,limit):
numbers.append(random.randint(1,10))
maxiumNum = max(numbers)
j = maxiumNum + 1
count = [0]*j
for i in range(j):
count[i]=0
for i in range(limit):
count[numbers[i]] +=1
n = count[0]
for i in range(1, j):
if (count[i] > n):
n = count[i]
mode = i
print("This is the mode = "+str(mode))
print("This is the array = "+str(numbers))my_mode() python
>>> from collections import Counter
>>> def my_mode(sample):
... c = Counter(sample)
... return [k for k, v in c.items() if v == c.most_common(1)[0][1]]
...
>>> my_mode(["male", "male", "female", "male"])
['male']
>>> my_mode(["few", "few", "many", "some", "many"])
['few', 'many']
>>> my_mode([4, 1, 2, 2, 3, 5])
[2]
>>> my_mode([4, 1, 2, 2, 3, 5, 4])
[4, 2]python mode
from scipy import stats
speed = [99,86,87,88,111,86,103,87,94,78,77,85,86]
x = stats.mode(speed)
print(x)Copyright © 2021 Codeinu
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