iterative binary search python
def binary_search(a, key):
low = 0
high = len(a) - 1
while low < high:
mid = (low + high) // 2
if key == a[mid]:
return True
elif key < mid:
high = mid - 1
else:
low = mid + 1
return Falseiterative binary search python
def binary_search(a, key):
low = 0
high = len(a) - 1
while low < high:
mid = (low + high) // 2
if key == a[mid]:
return True
elif key < mid:
high = mid - 1
else:
low = mid + 1
return Falsepython binary search
def binary_search(arr, item):
first = 0
last = len(arr) - 1
while(first <= last):
mid = (first + last) // 2
if arr[mid] == item :
return True
elif item < arr[mid]:
last = mid - 1
else:
first = mid + 1
return Falsebinary search python
# This is real binary search
# this algorithm works very good because it is recursive
def binarySearch(arr, min, max, x):
if max >= min:
i = int(min + (max - min) / 2) # average
if arr[i] == x:
return i
elif arr[i] < x:
return binarySearch(arr, i + 1, max, x)
else:
return binarySearch(arr, min, i - 1, x)binary search python
#binary search python
def binaryy(ar, ele):
low = 0
high = len(ar)-1
if ele not in ar:
return "Not Found"
while low <= high:
mid = (low + high) // 2
if ar[mid] < ele:
low = mid + 1
elif ar[mid] > ele:
high = mid - 1
else:
return mid
ar = [10, 20, 30, 40, 50]
ele = 55
print(binaryy(ar, ele))binary search in python
def binary_search_recursive(list_of_numbers, number, start=0, end=None):
# The end of our search is initialized to None. First we set the end to the length of the sequence.
if end is None:
end = len(list_of_numbers) - 1
if start > end:
# This will happen if the list is empty of the number is not found in the list.
raise ValueError('Number not in list')
mid = (start + end) // 2 # This is the mid value of our binary search.
if number == list_of_numbers[mid]:
# We have found the number in our list. Let's return the index.
return mid
if number < list_of_numbers[mid]:
# Number lies in the lower half. So we call the function again changing the end value to 'mid - 1' Here we are entering the recursive mode.
return binary_search_recursive(list_of_numbers, number, start, mid - 1)
# number > list_of_numbers[mid]
# Number lies in the upper half. So we call the function again changing the start value to 'mid + 1' Here we are entering the recursive mode.
return binary_search_recursive(list_of_numbers, number, mid + 1, end)binary search in python
def binary_search(group, suspect):
group.sort()
midpoint = len(group)//2
while(True):
if(group[midpoint] == suspect):
return midpoint
if(suspect > group[midpoint]):
group = group[midpoint]
if(suspect < group[midpoint]):
group = group[0: midpoint]
midpoint = (len(group)//2)Copyright © 2021 Codeinu
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